Question

A bus startng from rest Moves with a uniform acceleration of 0.1 meter/second for 2 minutes
Second
find
speed acquired
The distance travelled in the given period of time​

Answer 1

Answer:

We are given with certain Kinematics quantities of a bus.

Finding speed acquired:

Given:

Uniform accleration of the bus (a) = 0.1 m/s²

Time travelled by the bus (t) = 2 mins

Started from rest. (u = 0 m/s)

❒ Time taken = 2 mins = 2 × 60 = 120 s

By using 1st equation of motion,

\large{ \because{ \underline{ \boxed{ \rm{v = u + at}}}}}∵v=u+at

Plugging the given values to find the speed acquired:

➝ v = u + at

➝ v = 0 + (0.1)120

➝ v = 120 / 10 m/s

➝ v = 12 m/s

Finding distance travelled:

Now as we have got our final velocity, Initial velocity and accleration is given. So, By using 3rd equation of motion,

\large{ \because{ \underline{ \boxed{ \rm{ {v}^{2} - {u}^{2} = 2as}}}}}∵v2−u2=2as

Plugging the given values to find distance (s):

➝ v² - u² = 2as

➝ 12² - 0² = 2(0.1)s

➝ 144 = 0.2s

➝ s = 144 / 0.2 m

➝ s = 720 m

Hence, the required values of speed acquired and Distance travelled by the bus:

\large{ \therefore{ \underline{ \boxed{ \bf{ \green{12 \: m {s}^{ - 1} and \: 720 \: m}}}}}}∴12ms−1and720m

Answer 2

Answer:

Answer: The quantity of distance is measured by the area occupied below the velocity time graph. Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

Thus, bus will travel a distance of 720 m in the given time of 2 minute.