Question

A bus starts 40m/S velocity and attain the velocity 120m/s in 10 seconds,find its acceleration,and distance travelled in 10 second

Answer 1

Answer:

U = 40m/s

V = 120m/s

T =10s

A = v-u /t

A = 120 - 40 /10

A = 8m/s ^2

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Answer 2

Explanation:

Initial velocity, u = 40 m/s

Final velocity, v = 120 m/s

Time, t = 10s

Acceleration,

a = Change in velocity/Time

a = (v - u)/t

a = (120 - 40)/10

a = 80/10

a = 8 m/s²

Distance travelled,

S = ut + 1/2at²

S = 40×10 + 1/2×8×10×10

S = 400 + 400

S = 800m

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