a bus starts from rest accelerates uniformly with 4 metre per second at T10 second. a stone is dropped out of a window of the bus 2 metre high. what arethe magnitude of velocity and acceleration of the stone at 10.2 second
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The calculation is given below. We can take t as 10s.
t = time - 10 s
a = acceleration = 4 m/s²
u = initial velocity = 0 m/s
We need to find the final velocity v = u + at
= 0 + 4*10 = 40 m/s
t = time = 0.2 s
g = acceleration due to gravity = 10 m/s²
u = initial velocity = 0 m/s
v = 2 m/s. So the magnitude is 40.0 m/s.
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