Question

A bus starts from rest & moves with a
uniform accelesation of 1m per 2ndsquare for 5 minutes

find The speed acquired. /velocity
​

Answer 1

Answer:

v=u+at

u=0.

a=1m/s^2

t=5 minutes =5*60=300 sec

v=1*300=300m/s

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Answer 2

Answer :

➥ Final velocity of the bus = 300 m/s

Given :

➤ Intial velocity of the bus (u) = 0 m/s

➤ Acceleration of the bus (a) = 1 m/s²

➤ Time taken by the bus (t) = 5 min

To Find :

➤ Final velocity of the bus (v) = ?

Solution :

◈ Time taken = 5 min = 5 × 60 = 300 sec

Final velocity of the bus

From first equation of motion

⟾ v = u + at

⟾ v = 0 + 1 × 300

⟾ v = 0 + 300

⟾ v = 300 m/s

Hence, the final velocity of the bus is 300 m/s.

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Some releted equations :

⪼ s = ut + ½ at²

⪼ v = u + at

⪼ v² = u² + 2as