Question

A bus starts from rest and accelerates at the rate 2m/s². What will be it speed at the end of of 10 seconds? What is the distance covered by it in these 10 seconds?​

Answer 1

Answer:

A bus starts from rest and accelerates at the rate 2m/s². What will be it speed at the end of of 10 seconds? What is the distance covered by it in these 10 seconds?

Answer 2

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters