A bus starts from rest and attains 40 km h-1 velocity after 10 seconds calculate the acceleration of the bus in, (i)km h-2 (ii)m s-2.
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final velocity = u = 40 km/h = 40000/3600 m/s = 11.12 m/s
intial velocity = v = 0km/h = 0 m/s
time = t = 10 s = 0.0028 s
acceleration = a = ?
1)
a = v-u/t
a = 40-0/9
a = 40/9
a = 4.45 km/h²
2)
a = v-u/t
a = 11.12-0/0.0028
a = 11.12/0.0028
a = 3971.43 m/s²
intial velocity = v = 0km/h = 0 m/s
time = t = 10 s = 0.0028 s
acceleration = a = ?
1)
a = v-u/t
a = 40-0/9
a = 40/9
a = 4.45 km/h²
2)
a = v-u/t
a = 11.12-0/0.0028
a = 11.12/0.0028
a = 3971.43 m/s²
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