Question

.. A bus starts from rest and attains 40 km/h- velocity
after 10 Seconds calculate the acceleration of the
bus in (i) km-sqr ​

Answer 1

Answer:

0.305 km/h^2

Explanation:

v = 40 km/h

= 40×(5/18) ms^-1

= 11.11 ms^-1

a = 11.11/10 ms^-2

= 1.1 ms^-2

= (1.1×1000) /3600 km/h

= 0.305 km/h^2