Science, asked by niliyerchikalphava, 1 year ago

A bus starts from rest and attains 40 km/h velocity after 10 secs. calculate the acceleration of the bus in km/h 2 and m/s 2.

Answers

Answered by nikitasingh79
72
Given:
Intial velocity (u) = 0 (rest)
Final velocity(v) = 40 km/h
Time(t)= 10 sec = 10 / 3600=1/360hr

[ 1sec= 1/3600 h]

Acceleration (a)=( v-u)/t

Acceleration=( 40-0) /(1/360)
= 40/(1/360)= 40× 360= 14400km/h²

Final velocity (v)= 40 km /h
=( 40×1000)/3600= 100/9 m/sec

[ 1km= 1000m & 1 hr= 3600sec]

Acceleration (a)=( v-u)/t
= (100/9)/10 = 10/9 m/s²= 1.11.... m/s²
____________________________
Acceleration (a) in km/h²= 14400km /h²

Acceleration (a) in m/s²= 10/9 = 1.11..m/s²
____________________________
Hope this will help you....
Answered by prmkulk1978
33
Given :
Initial velcoity= u= 0m/s
Final velcoity =V=40km/hr=40x5/18 m/s=11.11m/s
time=10sec =10/60x60 =1/360 hr
Formula to be used :
a=v-u/t
*************************************************************************
1. Calculating acceleration in m/s :
a=(11.11-0)/10
=1.111m/s²

2. Calculating aceeleration in Km/Hr
a=(40-0)/1/360
=14400km/hr²
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