Question

A bus starts from rest and attains 40km/h velocity after 10second calculate the acceleration of the bus in km/2h

Answer 1

Answer:

Given :

$\textsf{Initial Velocity = 0}$

$\textsf{Final velocity = 40 km/hr}$

$\sf{Time \:taken = 10 s = \dfrac{10s}{1hr}=\dfrac{10s}{3600s}=\dfrac{1}{360}hr}$

To find :

$\sf{The\: Acceleration \:of \:the\: bus\: in \:{km/hr}^{2}}$

Taken :

To find the Acceleration use the formula of Acceleration:

$\sf\boxed{A=\dfrac{V-U}{T}}$

Where ,

A = Acceleration

V = Final velocity

U = Initial velocity

T = Time

Solution :

$:\implies\sf{A=\dfrac{40km-0}{\dfrac{1}{360}hr}}$

$\:\:\:\::\implies\sf{A=\dfrac{40km}{\dfrac{1}{360}hr}}$

$\:\:\:\:\:\:\:\::\implies\sf{A=\dfrac{40}{1}km\div\dfrac{1}{360}hr}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\::\implies\sf{A=\dfrac{40}{1}km\times\dfrac{360}{1}hr}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\::\implies\sf{A={14400km}^{2}}$

Answer :

So , the Acceleration of the bus in km/hr² is $\sf{{14400km}^{2}}$