a bus starts from rest and attains 40km/h velocity after 10sec .calculate the acceleration of the bus in kmh^-2..
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Answer:
acceleration of the bus a=14400 kmh^-2
Explanation:
10 seconds = 1/360 hours
now,
v=u+at
40 = 0 + a x 1/360
40 = a/360
40*360 = a
a=14400 kmh^-2
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