A bus starts from rest and attains 40km/hr velocity after 10 seconds. Calculate the acceleration of Bus (i) km/h2 (ii) m/s2
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Given, initial velocity of bus u = 0
final velocity v = 40km/h or 100/9 m/s
time period t = 10second or 1/360hour
Now,
(i) acceleration in km/h^2
a = v-u/t
= (40 - 0)/(1/360)
= 40 × 360
= 14400km/h^2
(ii) acceleration in m/s
a = (100/9 - 0)/10
= 100/90
= 1.111 m/s
【 Hope it helps you 】
Given, initial velocity of bus u = 0
final velocity v = 40km/h or 100/9 m/s
time period t = 10second or 1/360hour
Now,
(i) acceleration in km/h^2
a = v-u/t
= (40 - 0)/(1/360)
= 40 × 360
= 14400km/h^2
(ii) acceleration in m/s
a = (100/9 - 0)/10
= 100/90
= 1.111 m/s
【 Hope it helps you 】
jassijassar:
40-0=50???
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