A bus starts from rest and attains 40kmh-1 velocity after 10s calculate the acceleration of the bus in kmh-1 and ms-2
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Answered by
1
acceleration=change in velocity/time.
=40/(10/3600)
=14400km/h^2.
=40000/10=4000m/s^2
=40/(10/3600)
=14400km/h^2.
=40000/10=4000m/s^2
Answered by
0
Formula for Acceleration,
• Acceleration = (v - u) / t
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= (40 kmph - 0 kmph) / [10 s × (1 hr / 3600 s)]
= 1400 km/hr
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∴ Acceleration is 1400 km/hr
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