A bus starts from rest and attains a speed of 36 km/h in 10 minutes while moving with uniform acceleration. Calculate the acceleration of the bus.
Answers
Answer:
Initial velocity or u= 0 (as the bus starts from rest then the initial velocity will be zero)
Final velocity or v= 36 km/h
We need to change 36 km/h into m/s then we have to multiply it with 5/18 m/s.
36 × 5/18 = 10 m/s (final velocity)
Time or t= 10 min
1 minutes = 60 secs
10 min = 10 × 60 s
= 600 s (time in seconds)
Acceleration = v-u/t
= (36-0/600) m/s^2
= 36/600 m/s^2
= 3/50 m/s^ 2 = 0.06 m/s^2.
Thus, acceleration is 0.06 m/s^2. (Here, m/s^2 means metre per second square).
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Initial velocity or u= 0 (as the bus starts from rest then the initial velocity will be zero)
Final velocity or v= 36 km/h
We need to change 36 km/h into m/s then we have to multiply it with 5/18 m/s.
36 × 5/18 = 10 m/s (final velocity)
Time or t= 10 min
1 minutes = 60 secs
10 min = 10 × 60 s
= 600 s (time in seconds)
Acceleration = v-u/t
= (36-0/600) m/s^2
= 36/600 m/s^2
= 3/50 m/s^ 2 = 0.06 m/s^2.
Thus, acceleration is 0.06 m/s^2. (Here, m/s^2 means metre per second square).
Plz mark me the brainliest.