Question

A bus starts from rest and attains a speed of 36km/h in 10min. while moving with uniform acceleration. calculate the acceleration of the bus​

Answer 1

Answer:

first convert 36km/hr into m/s

so,36×(5/18)m/s

=10m/s

Secondly Convert Time Into Seconds,

so,10×60

=600 seconds

We know that ,

a=(v-u)/t

a=10-0/600

a=10/600

a=1/60 m/s2

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Answer 2

Answer:

Given that final speed = 36 km/hr

Initial speed =0

And time =10 min.

Change time in hours 10/60 hr

So ,

We know that

final speed - initial speed Acceleration - - - - - - - - - - - - - - - - - - - - -

Final time - initial time

36-0

Acceleration =------------

10/60

Acceleration =60×36/10

Acceleration = 216 km/h^2 or

Because 1 km/h^2 = 7.78×10^-5 m/s^2

Acceleration = 216×7.78×10^-5

Acceleration =1680.48×10^-5

Or

Acceleration = 1.68048×10^-2 m/s^2

Hope it helps u