Question

a bus starts from rest and attains a speed of 36km per hour in 1 minute while moving with uniform acceleration along a straight Road. calculate the acceleration of the bus.

Answer 1

Hi friends we know that equation of newton motion law v= u+ at --------------1
Given v=36 ×5/18 = 10 m/s
and u=0 all value put in question ---------18
10=0+a ×60
a=1/6
a= 0.16 m/s^2 answer
i hope you understand

Answer 2

✬ Acceleration = 0.17 m/s² ✬

Explanation:

Given:

• A bus stars from rest (u) = 0
• Bus attains speed (v) of 36 km/h.
• Time (t) taken to attain 36 km/h is 1 minute.

To Find:

• What is the acceleration (a) of the bus ?.

Formula to be used:

• First law of motion
• v = u + at

Solution: Here, final velocity (v) is in km/h so we need to change it in m/s.

➨ 36 km/h = 36 $\times$ 5/18 m/s

➨ ( 2 $\times$ 5 ) m/s

➨ 10 m/s ( Final Velocity )

Changing time into seconds

➨ 1 minute = 60 seconds

Now, put the values on formula

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 10 = 0 + a $\times$ 60

$\implies{\rm }$ 10 = 60a

$\implies{\rm }$ 10/60 = a

$\implies{\rm }$ 0.166 m/s² or 0.17 m/s² = a

Hence, the acceleration of the bus is 0.17 m/s².