Question

A bus starts from rest and attains a speed of 54km/h
in 10 minutes while moving with uniform acceleration. Calculate acceleration of thr bus? ​

Answer 1

Answer:

Acceleration is equal to 0.025 m/s²

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Final velocity = v = 54 km/hr

• Time taken = t = 10 minutes = 600 seconds

To find :

Acceleration of the bus

54 km/hr = 54×5/18 = 3×5 = 15 m/s

Acceleration = (v-u) / t

Acceleration = (15-0)/600

Acceleration = 15/600

Acceleration = 1/40

Acceleration = 0.025 m/s²

The acceleration of the bus is equal to 0.025 m/s²

Answer 2

✯✯ QUESTION ✯✯

A bus starts from rest and attains a speed of 54km/h in 10 minutes while moving with uniform acceleration. Calculate acceleration of thr bus?

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✰✰ ANSWER ✰✰

$\implies\tt{Initial\:Velocity(u)=0m/s}$

$\implies\tt{Final\:Velocity(v)=54km/hr=15m/s}$

$\implies\tt{Time\:Taken(t)=600sec}$

$\implies\tt{Acceleration(a)=?}$

➥Using Formula : -

$\implies\tt{\small{\boxed{\bold{\bold{\blue{\sf{Acceleration=\dfrac{v-u}{t}}}}}}}}$

➥Putting Values : -

$\implies\tt{a=\dfrac{15-0}{600}}$

$\implies\tt{a=\dfrac{15}{600}}$

$\implies\tt{a=\dfrac{1}{40}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{a}\orange{=}\purple{0.025{m}^{2}}}}$

☛So ,The acceration of the bus is 0.025m/s²