A bus starts from rest and attains a velocity of 36 kilometre per hour in 5 seconds find the acceleration produced and the distance travelled by the bus in this 5 seconds
Answers
A bus starts from rest means the initial velocity of the bus is 0 m/s and attains a velocity of 36 km/hr in 5 sec.
From above data we have; u = 0 m/s, v = 36 km/hr and t = 5 sec.
We have to find the acceleration and distance travelled by the bus.
To convert km/hr into m/s multiply with 5/18.
⇒ v = 36 × 5/18 = 10 m/s
For acceleration:
Using the First Equation Of Motion:
v = u + at
Substitute the known values,
→ 10 = 0 + a(5)
→ 10 = 5a
→ 2 = a
Therefore, the acceleration of the bus is 2 m/s².
For distance:
Using the Second Equation Of Motion:
s = ut + 1/2 at²
Substitute the values,
→ s = 0(5) + 1/2 × 2 × (5)²
→ s = 0 + 1(25)
→ s = 25
Therefore, the distance covered by the bus is 25 m.
Answer:
Acceleration = 2 m/s²
Distance travelled = 25 metres
Explanation:
Given :
- Initial velocity = u = 0 m/s
- Final velocity = v = 36 km/hr
- Time taken = t = 5 seconds
To find :
- Acceleration of the bus
- Distance covered by the bus
Using the first equation of motion :
V=u+at
36 km/hr = 36×5/18 = 10 m/s
10=0+a×5
10=5a
a=10/5
a=2 m/s²
The acceleration of the bus is equal to 2 m/s²
Using the third equation of motion :
V²-u²=2as
10²-0²=2×2×s
100=4s
s=100/4
s=25 metres
The distance travelled is equal to 25 metres