A bus starts from rest and attains a velocity of 36km/h in 5 seconds find theaccelration produced and distance travelled by the bus in these 5 seconds
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Given, u = 0 km/h ( as body starts from rest )
v = 36 km/h
So, to convert km/h to m/s, multiply it by 5/18
Thus, 36 × 5/18 = 10 m/s
t = 5s
So, a = v - u / t
= 30 - 0 / 5
= 10/5
= 2m/s^2
Distance 's' = ut + 1/2 at^2 (II nd equation)
=0 × 5 + 1/ 2 × 2 ×5 × 5
=0 + 25
= 25 m
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