Question

a bus starts from rest and attains a velocity of 46m/s after 10 seconds.find the acceleration and the distance travelled in 5 seconds and in 10 seconds.​

Answer 1

Explanation:

Given,

initial velocity is rest => u=0

Final Velocity =46m/s at 10 seconds

To Find;

Acceleration,

Distance at 5 sec

Distance at 10 sec

Forumals :-

$a = \frac{(v - u)}{t}$

Distance =Speed x Time

Solution:-

Accelaration=(46-0)/10 m/s²

=46/10 m/s²

=4.6 m/s²

Velocity at 5 sec = 4.6*5=23m/s

Distance travelled at 5 sec =23*5 m=115 m

Velocity at 10 sec = 46 m/s

Distance travelled at 10 sec= 46*10 =460 m