Question

.,A bus starts from rest and attains speed of 36 km/hr in 10 minutes while moving with uniform
acceleration. What will be the acceleration of bus?
a.) 0.21 m/s2
b.) 0.017 m/s2
c.) 0.45 m/s2
d.) 0.123 m/s2

Answer 1

Given:-

• Initial velocity ,u = 0m/s
• Final velocity ,v = 36km/h
• Time taken ,t = 10min

To Find :-

• Acceleration ,a

Solution :-

We have to calculate the acceleration of the bus .

As we know that acceleration is defined as the rate of change in velocity .

Conversion of unit

➻ v = 36×5/18

➻ v = 2×5

➻ v = 10m/s

And,

➻ t = 10×60

➻ t = 600s

Now, calculating the acceleration .

Using Formula

• a = v-u/t

substitute the value we get

➻ a = 10-0/600

➻ a = 10/600

➻ a = 1/60

➻ a = 0.0166 ≈ 0.017 m/s²

• Hence, the acceleration of the bus will be 0.017 m/s².

So, the required option is (b) 0.017m/s².

Answer 2

Answer:

(b) 0.017 m/s^2

Explanation:

Wehave,

Initial velocity = 0m/s

Final velocity = 36m/hr

Time taken = 10min = 600sec

We have to find the acceleration

So, formula of acceleration is

${\sf\tt\bf{\red{\boxed{a = \frac{v - u}{t} }}}}$

Putting values in the formula

$\sf{a = \frac{10 - 0}{600}}$

$\sf{a = \frac{1}{60}} =0.0166666667$

$\sf{a =\pink{0.017m/s^2}(approx)}$