Question

A bus starts from rest and moves down a hill with constant acceleration.The bus travels a distance of 400 m in 10 seconds.If mass of the bus is 5 metric tonne,then what will be its acceleration and force acting on it?​

Answer 1

Answer:

Heyy your answer is: 40,000 N

Answer 2

$\sf GivEn \begin{cases} & \sf{Initial\; Velocity, u = \bf{0\;m/s}} \\ & \sf{Distance, d = \bf{400\;m} } \\ & \sf{Time, t = \bf{10\;s}} \\ & \sf{Mass, m = 5\;metric\;tonne = \bf{5000\; kg}}\end{cases}$

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☯ By using 2nd equation of motion,

$\star\;{\boxed{\sf{\purple{s = ut + \dfrac{1}{2} at^2}}}}$

$:\implies\sf 400 = 0 \times 10 + \dfrac{1}{2} a(10)^2$

$:\implies\sf 400 = 0 + \dfrac{1}{2} \times 100a$

$:\implies\sf 400 = \dfrac{1}{ \cancel{2}} \times \cancel{100}a$

$:\implies\sf 400 = 50a$

$:\implies\sf a = \cancel{ \dfrac{400}{50}}$

$:\implies{\boxed{\frak{\pink{a = 8\;m/s^2}}}}\;\bigstar$

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☯ Now, As we know,

$\star\;{\boxed{\sf{\purple{F = ma}}}}$

$:\implies\sf F = 5000 \times 8$

$:\implies{\boxed{\frak{\pink{F = 40,000\;N}}}}\;\bigstar$

$\therefore\;{\underline{\sf{Hence,\;Force\;acting\;on\;body\;is\;40,000\;N.}}}$