Question

A bus starts from rest and moves down a hill with constant acceleration.The bus travels a distance of 400 m in 10 seconds.If mass of the bus is 5 metric tonne,then what will be its acceleration and force acting on it?​

Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Initial velocity ,u = 0m/s

• Distance,d=400m

• Time,t=10sec

• Mass,m=5 Metrictonne OR, 5000kg

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

• Force ( F) acting on body

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

$\underline{\:\textsf{ As we know that :}}$

$\star\;{\boxed{\sf{\purple{s = ut + \dfrac{1}{2} at^2}}}}$

$(\bf 2nd \: equation \: of \: motion)$

$\underline{\:\textsf{ Now, put the given values :}}$

$\dashrightarrow \sf 400 = 0 \times 10 + \dfrac{1}{2} a(10)^2$

$\dashrightarrow \sf 400 = 0 + \dfrac{1}{2} \times 100a$

$\dashrightarrow \sf 400 = \dfrac{1}{ \cancel{2}} \times \cancel{100}a$

$\dashrightarrow \sf 400 = 50a$

$\dashrightarrow \sf a = \cancel{ \dfrac{400}{50}}$

$\dashrightarrow {\boxed{\frak{\purple{a = 8\;m/s^2}}}}$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \: Acceleration = 8 \: m/s ^{2}}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\sf A.T.Q:-$

We are asked to find Force.

$\underline{\:\textsf{ We know that :}}$

$\star\;{\boxed{\sf{\purple{F = ma}}}}$

$\dashrightarrow \sf F = 5000 \times 8$

$\dashrightarrow {\boxed{\frak{\purple{F = 40,000\;N}}}}$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\underline{\textsf{ Force acting on body is </p><p>\textbf{ 40000N}}}.$

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

this is the answer

Explanation:

hope this help you...

..