Question

A bus starts from rest and moves with a uniform acceleration of 1ms^-2 for 5 min. Calculate the speed acquired and the distance travelled by the bus

Answer 1

Answer: speed aquired = 300m/s

Distance travelled = 4500m or 4.5 km

Explanation:

accelaration of bus = 1m/s

time in seconds = (5)(60) = 300 sec

So for speed aquired,

We have,

v= u+ at

v=0+(1)(300)

v= 300m/s

For distance travel we have,

s = ut+ 1/2 at^2

s= 1/2 (1) (300)^2

s= 4500 m or 4.5 km

Answer 2

Answer:

See the video for explaining. Just think and note the values firsr in notebook

Explanation: