Question

A bus starts from rest and moves with a uniform acceleration of 1 metre per second for 5 minutes.
calculate the speed acquired and distance travelled by the bus

Answer 1

given time = 5 minute= 300s
u= 0m/s
a=1m/s²

v= u+ at
v=0+ 1m/s²*(5*60)s
= 300m/s

where v = final velocity
u= initial velocity
a= acceleration
t= time taken

Answer 2

hσlα!!!!

________

gívєn

ínítíαl vєlσcítч = 0 mѕ^-1

Acceleration (a) = 1ms^-2

Time (t) = 5mins = 5 × 60 s = 300s

SOLUTION

we know a kinematical equation

v = u+at

= 0 + (1)(300)

v = 300ms^-2

Speed = 300ms^-2

Speed = distance /time

Distance = speed × time

= 300 × 300

Distance = 90000m

[ = 90000/1000 = 90km ]

__________________


HOPE THIS HELPS YOU :D