Question

A bus starts from rest and moves with a uniform acceleration of 1 m\s2 for 5 minutes.Calculate the distance covered by the bus during this time.​

Answer 1

Given that:

• Initial velocity = 0 mps
• Acceleration = 1 m/s sq.
• Time = 5 minutes

To calculate:

• The distance travelled

Solution:

• The distance = 45000 m

Knowledge required:

• SI unit of acceleration = m/s sq.
• SI unit of distance = m
• SI unit of velocity = m/s
• SI unit of time = second

Using concepts:

• Formula to convert min-sec.
• Second equation of motion

Using formulas:

• Converting min into sec =>

• 1 min = 60 seconds

• 2nd equation of motion =>

• s = ut + ½ at²

Where, s denotes displacement or distance or height, a denotes acceleration, u denotes initial velocity and t denotes time taken.

Required solution:

~ Converting minutes into seconds!

→ 1 min = 60 seconds

→ 5 min = 5 × 60 seconds

→ 5 min = 300 seconds

• Henceforth, converted!

~ Now let us find out the distance travelled by using second equation of motion!

→ s = ut + ½ at²

→ s = 0(300) + ½ × 1(300)²

→ s = 0 + ½ × 1(300)²

→ s = 0 + ½ × 1 × 90000

→ s = 0 + ½ × 90000

→ s = 0 + 1 × 45000

→ s = 0 + 45000

→ s = 45000 m

→ Distance = 45000 m

• Henceforth, solved! $\:$

Answer 2

Answer:

$\green{ \boxed{\dag \: \: \bf \: distance \: \: \: s = 45 \: km}}$

Explanation:

Given,

$\bf \odot \: \: \bf \: initial \: velocity \: \: u = 0 \: \: \: \red{ \{ \: at \: rest \: \}} \\ \bf \odot \: \: \: acceleration \: \: a \: = 1 \: m {s}^{ - 1} \\ \bf \odot \: \:time \: \: \: t = 5 \: min = 5 \times 60 \: = 300 \: s \\ \\ \mathbb \pink { \bf\: we \: have \: to \: find} \\ \bf \odot \: \:distance \: \: = \: s \\ \\ \orange{\bf \: we \: know \: that \: } \\ \\ \: \bf s = ut + \frac{1}{2} a {t}^{2} \\ \: \: \: \: = 0\times 300 + \frac{1}{2} \times 1 \times {(300)}^{2} \\ \: \: \: \: = 0 + \frac{1}{2} \times 90000 \\ \: \: \: \: = 45000 \: m \\ \: \: \: \: = \frac{45000}{1000} \: km \\ \: \: \: \: = 45 \: km \\ \\ \green{ \boxed{\therefore \bf \: distance \: \: \: s = 45 \: km}}$