Question

a bus starts from rest and moves with a uniform velocity of 40 m/s in 8 seconds find 1) the acceleration of the bus. 2) the distance covered by the bus​

Answer 1

Answer:

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Answer 2

Answer:

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒

2

1

at

2

=vt−48

⇒

2

1

(1)t

2

=10t−48

⇒t

2

−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus

Explanation:

answer is t=8s