Question

a bus starts from rest and moves with acceleration a=2m/s2 the ratio of the distance covered in 6th second to the covered in 6 second is

Answer 1

Please reply if my answer is correct

Answer 2

Given that acceleration (a) = $2\frac { m }{ { sec }^{ 2 } }$

       Initial velocity u = 0

       Time (t) = 6 sec

       Final velocity V =?

       V = u + at

       $V\quad =\quad 0+2\times 6\quad =\quad 12\frac { m }{ sec }$

       Distance traveled S = ?

       $V^2 - U^2 = 2as$

   $122-U^2\quad =\quad 2\times 2\times S$

       144 - 0 = 4S

$S\quad =\quad \frac { 144 }{ 4 } = 36 m$

The distance covered in 6th second = 36 m