Question

A bus starts from rest and moves with constant acceleration . At the same time, a car travelling with a constant velocity 16 m/s overtakes and passes the bus. After how much time and at what distance, the bus overtakes the car?

Answer 1

Answer:

t=4s , d= 64m

Explanation:

The position of bus after time t is given as

x 1=1/2at^2

The position of car after time t is given as

x 2 =ut

Hence when the bus passes the car,

x 1 =x 2

⟹ 1/2 at^2 =ut

⟹t= 2u/a = 2×16m/s / 8m/s =4s

Hence the distance at the crossing=ut

=16m/s×4s=64m

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