Question

A bus starts from rest and picks up a velocity of 90 km/h in 1/2 minute. Calculate the uniform acceleration of the bus in m/s²​

Answer 1

Answer:

u = 0

v = 90kmph = 90 x 5/18 = 25 m/s

t = 30 s

a = v - u / t

a = 25-0/30

a = 5/6 = 0.833 m/s²

Answer 2

✪ AnsWer : ✪

• Initial velocity (u) of the bus is 0 m/s
• Final velocity (v) of the bus is 90 km/h
• Time interval (t) = ½ minute = 0.5 min = 30 second.

★ Final velocity (v) :

→ Final velocity = 90 km/h

→ Final velocity = 90 × (5/18)

→ Final velocity = 450/18

→ Final velocity = 25 m/s

★ Acceleration (a) :

↠Acceleration = (v - u)/t

↠Acceleration = (25 - 0)/30

↠Acceleration = (25)/30

↠Acceleration = 0.84 m/s²

• Therefore, uniform acceleration of the bus is 0.84 m/s².