Question

A bus starts from rest and then moves with a constant acceleration of 2m/s
square. Calculate its time of travel if its final velocity is 20 m/s

Answer 1

Answer:

The position of bus after time t is given as x

b

=

2

1

at

2

The position of car after time t is given as x

c

=ut

Hence when the bus passes the car,

x

b

=x

c

⟹

2

1

at

2

=ut

⟹t=

a

2u

=

8m/s

2

2×16m/s

=4s

Hence the distance at the crossing=ut=16m/s×4s=64m

Explanation:

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