A bus starts from rest and then moves with a constant acceleration of 2m/s square. Calculate its time of travel if its final velocity is 20 m/s with process
Answers
Velocity of bus V
b
=0 , Velocity of cyclist V
c
=20m/s,
Acceleration of bus a
b
=2m/s
2
Acceleration of cyclist a
c
=0
Relative velocity V
cb
=V
c
−V
b
=20m/s
Relative acceleration a
cb
=a
c
−a
b
=−2m/s
2
Relative separation =96m
Using s=ut+
2
1
at
2
⇒96=20t−
2
1
2t
2
⇒t
2
−20t+96=0
Solving the equation , we get t=8s and t=12s
Hence, after 8s, cyclist will overtake the bus.
Answer:
Velocity of bus V
b
=0 , Velocity of cyclist V
c
=20m/s,
Acceleration of bus a
b
=2m/s
2
Acceleration of cyclist a
c
=0
Relative velocity V
cb
=V
c
−V
b
=20m/s
Relative acceleration a
cb
=a
c
−a
b
=−2m/s
2
Relative separation =96m
Using s=ut+
2
1
at
2
⇒96=20t−
2
1
2t
2
⇒t
2
−20t+96=0
Solving the equation , we get t=8s and t=12s
Hence, after 8s, cyclist will overtake the bus.