Question

A bus starts from rest at a constant acceleration of 5ms2. At the same time the car starts moving with constant velocity 50ms

Answer 1

DISTANCE COVERED BY CAR WILL EQUAL TO THE DISTANCE COVERED BY BUS.

UT + 1/2 AT² = 50T0×T+1/2×5×T² = 50T5/2 T² = 50T5/2 T = 50

USING 3RD EQUATION OF UNIFORMLY ACCELERATED MOTION,

V² = U² + 2ASV² = 0² + 2×5×1000V² = 10×1000V = √10000V = 100 M/S

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