Question

a bus starts from rest attains a speed of 72km/h for 10sec calculate distance travelled and acceleration of the bus​

Answer 1

Given:-

•final velocity =72km/h

=72×5/18

=20m/s

•initial velocity =0m/s

•time=10s

☆Use equations of motion

$v = u + at$

20 = 0+ a(10)

20 = a(10)

a=2m/s2

${v}^{2} = {u}^{2} + 2as \\ s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ s = \frac{400 - 0}{2 \times 2} \\ s = \frac{400}{4} \\ s = 100m$

hope it helps!

Good luck ♧♧

Answer 2

Initial speed of the body, u = 0 m/s

Final speed of the body, v = 72 km/h = 20 m/s

Time taken to cover the distance, t = 10 s

Distance covered by the bus = s

Acceleration of the bus = a

By using the formula, v = u + at

• 20 = 0 + (a)(10)

• 20 = 10a

• a = $\dfrac{20}{10}$

• a = 2 m/s²

Now, by using the formula, s = ut + $\dfrac{1}{2}$ at²

• s = 0 × 10 + $\dfrac{1}{2}$ × 2 × (10)²

• s = 100 m

$\bold{Hope\;it \; helps\;!}$