Question

A bus starts from rest. If its speed increases to 20m/sec accelerating at a uniform rate of 2.5m/sec^2, find the time interval.​

Answer 1

$\boxed{\rm{\orange{Given \longrightarrow }}}$

$\sf{Initial \ speed [u] =0m/s}$

$\sf{ Final Speed [v] = 20m/s}$

$\sf{ Acceleration [a]= 2.5m/s^2}$

$\boxed{\rm{\pink{Find \longrightarrow }}}$

Time interval?

$\boxed{\rm{\orange{solution \longrightarrow }}}$

Formula to be used

$\boxed{\bf{ a= \dfrac{v-u}{t} }}$

Put value in the formula we get,

$\sf{ 2.5= \dfrac{20-0}{t} }$

$\sf{t= \dfrac{20}{2.5}}$

$\sf{t=8 sec}$

$\boxed{\bf{\purple{\underline{ \therefore Time\ interval = 8 sec}}}}$

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Answer 2

Answer:

$\boxed{\rm{\purple{Given \longrightarrow }}}$

$\sf{Initial \ speed [u] =0m/s}$

$\sf{ Final Speed [v] = 20m/s}$

$\sf{ Acceleration [a]= 2.5m/s^2}</p><p>$

$\boxed{\rm{\pink{Find \longrightarrow }}}$

Time interval?

$\boxed{\rm{\orange{solution \longrightarrow }}} </p><p>$

Formula to be used

$\boxed{\bf{ a= \dfrac{v-u}{t} }} </p><p></p><p>$

Put value in the formula we get,

$\sf{ 2.5= \dfrac{20-0}{t} }$

$\sf \pink{t= \dfrac{20}{2.5}}$

$\sf \red{t=8 sec}$

$\boxed{\bf{\purple{\underline{ \therefore Time\ interval = 8 sec}}}}$

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