a bus starts from rest.if the acceleration is 0.5m/s what will be the velocity at the end of 2 min and what distance will cover during that time.
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Initial Velocity=0
Acceleration=0.5 m/s
Time=2 min or 120 Seconds
According to the equation of motion
v=u+at
v=0+0.5*120
v=0+60
v=60
Therefore, Final Velocity or velocity at the end of 2 min is 60.
According to the Equation of Motion
s=ut+1/2atsquare
s=0*120+1/2 * 0.5*14400
s=0+0.5*7200
s=3600
Therefore distance travelled is 3600 m
Acceleration=0.5 m/s
Time=2 min or 120 Seconds
According to the equation of motion
v=u+at
v=0+0.5*120
v=0+60
v=60
Therefore, Final Velocity or velocity at the end of 2 min is 60.
According to the Equation of Motion
s=ut+1/2atsquare
s=0*120+1/2 * 0.5*14400
s=0+0.5*7200
s=3600
Therefore distance travelled is 3600 m
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