Question

A bus starts from rest. If the acceleration is 2m/s^2, find 1) the distance travelled. 2) the velocity after 2 second

Answer 1

Answer:4

Explanation: refer to the attached document

Answer 2

Answer:

Explanation:

Here, we have

initial velocity, u = 0 m/s

Acceleration, a = 2 m/s²

Time taken, t = 2 seconds

To find,

Distance covered, s = ?

Final velocity, v = ?

We know that

1st and 2nd equations of motion,

v = u + at and s = ut + 1/2at²

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 2 × 2

⇒ v = 4 m/s

Hence, the final velocity of bus is 4 m/s

Now, the distance covered,

s = ut + 1/2at²

⇒ s = 0 × 2 + 1/2 × 2 × (2)²

⇒ s = 1/2 × 2 × 4

⇒ s = 4 m

Hence, the distance covered is 4 m.