Question

A bus starts from rest. If the acceleration of the bus is 0.5m/sec2 what will it's velocity at end of 2 min and what distance will cover during that time ​

Answer 1

Answer:

Explanation:

u= 0

a= 0.5

t= 2x60= 120 s

s= ut + 1/2at^2

s= 0x120 + 1/2(0.5) x 120^2

s= 0 + 0.25 X 14400

s= 0.25 x 14400

s= 360 m

2as= v^2 - u^2

2 x 0.5 x 360= v^2 - 0^2

360 = v^2

$\sqrt{360}$ = v

18.97= v

v= 18.97 v