Question

A bus starts from rest . If the acceleration of the bus is 0.5 m/s2, what will be it's velocity at the end of 2 minutes and what distance will it cover during that time?


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Answer 1

Answer:

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Answer 2

Final velocity of bus is 60 m/s and bus will cover 3600 m distance during that time.

Solution

As the bus starts from rest, initial velocity of bus (u) = 0 m/s

Acceleration of bus(a) = 0.5 m/s²

Time (t) = 2 minutes.

= (2 × 60) s

= 120 s

☢ Using 1st equation motion :

● v = u + at

⇒ v = 0 + (0.5 × 120)

⇒ v = 0 + 60

⇒ v = 60 m/s

∴Velocity at the end of 2 minutes = 60 m/s

☢ Using 2nd equation motion :

● s = ut + ½ at²

⇒ s = (0 × 120) + ½(0.5 × 120²)

⇒ s = 0 + ½(0.5 × 14400)

⇒ s = ½(7200)

⇒ s = 3600 m

∴ Distance covered by bus = 3600 m