A BUS STARTS FROM REST IF THE ACCELERAYION IS 2M/S FIND THE DISTANCE TRAVELLED nd the velocity after 2 seconds
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u = 0
a = 2
t = 2
then we will use 1st equation of motion
V =u + at
v= 0+2×2
v = 4
its velocity after 2 seconds is 4 m/s
for distance we will use 2nd equation
s =ut +½at^2
so distance travelled after 2 sec is 4 metre
hope this help
if u hv any doubt , comment me
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