A bus Starts from rest moving with acceleration 2m/s². A cyclist 96m behind the bus starts simultaneously towards the bus at 20m/s l. After what time he will be able to overtake the bus?
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Given;
acceleration =2m/s².
distance needed by the cyclist to overtake =96m.
speed of cyclist =20m/s.
time=?
We know time=d/s,
hence,
= 96/20.
= 4.8s
Therefore the time required by the cyclist to overtake the
acceleration =2m/s².
distance needed by the cyclist to overtake =96m.
speed of cyclist =20m/s.
time=?
We know time=d/s,
hence,
= 96/20.
= 4.8s
Therefore the time required by the cyclist to overtake the
poojan3:
but how...
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