Question

a bus starts from rest on a straight road and acceleration uniformly for 5 second what is the acceleration if its velocity at the end of these 5sec in 25cm/s​

Answer 1

Explanation:

acceleration = 5 cm / sec²

initial velocity=u= 0

final velocity = v= 25 cm/sec

time = t= 5 seconds

acceleration = a=?

v= u+at

25 = 0 + a×5

=> a = 25/5 = 5cm /sec²

Answer 2

Given

Bus starts from rest.

Final velocity (v) = 25 cm/s

Time(t) = 5 seconds.

To find

Acceleration of bus.

Solution

As the bus starts from rest, so for the bus,

➙ Initial velocity (u) = 0

➙ Final velocity (v) = 25 cm/s

We know equation of kinematics :

➥ a = (v - u)/t

Here, a = acceleration,u = initial velocity & v = final velocity.

Putting values we get :

⟼ a = (25 - 0)/5

⟼ a = (25 cm/s)/5 s

⟼ a = 5 cm/s²

Therefore,

Acceleration of bus = 5 cm/s²

_______________________________

More such equations :

➝ v = u + at

➝ v² = u² + 2as

➝ s = ut + ½at²