A bus starts from rest with a uniform acceleration of 0.5 for 4 minutes
Find
Speed
Distance travelled
Answers
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Explanation:
a=0.5m/s^2
u=0m/s
t=4min means 4×60=240s
v=u+at
v=0+5÷10×240
v=5×24
v=120m/s
s=ut+1÷2 at^2
s=0t+1÷2×5÷10×240×240
s=14400m
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