Question

A bus starts from rest with an acceleration of 1m/s . A man who is 48m behind the bus starts with a uniform velocity 10 m/s . Find minimum time after which the man will catch the bus.​

Answer 1

Answer:

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒

2

1

at

2

=vt−48

⇒

2

1

(1)t

2

=10t−48

⇒t

2

−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus