A bus starts from terminal A and covers a distance of 70 km due East in 30 minutes to reach terminal B. It stays there for three hours and then returns to the initial position in the same interval of time. What is the magnitude of the average velocity of the bus?
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Answers
Answer:
Average velocity = 0
Explanation:
Average Velocity = Net Displacement / Total time taken
Here since bus returns to its intial position , therefore displacement = 0
Therefore average velocity = 0
Hope this helps you
Answer :-
Magnitude of average velocity of the bus is 0 km/h .
Explanation :-
We have :-
→ Distance from Terminal A to B = 70 km
→ Time taken (from A to B) = 30 min = 0.5 h
→ Staying time = 3 h
→ Time taken (B to A) = 0.5 h
______________________________
To calculate average velocity of the bus, we have to firstly calculate the total displacement of the bus and time taken.
Total displacement :-
Here, the bus starts from Terminal A and finally returns to Terminal B.
So, the initial and final points of the bus are same.
Thus, displacement of the bus is zero .
Total time :-
= (0.5 + 0.5 + 3) hrs
= 4 hours
Average velocity :-
= Total displacement/Total time
= 0/4
= 0 km/h