Question

A bus starts from the stop and take 50s to get the speed of 10m/s . if the mass of the bus along with passengers is 10000kg. calculate the force applied by the engine of bus to push the bus at the speed of 10m/s

Answer 1

Given
v=10m/s
u=0m/s
t=50s
m=10000kg
F=?
According to Newton's II law of motion: F=ma
a is acceleration
a= v-u/t
F=m(v-u)/t
F=10000* (10-0)/50
F= 10000* 10/50
F= 2000N

Hope it helps you,
thank you.

Answer 2

v = u + a t

u = 0 ,  t = 50 sec.  v = 10 m/s

=> a = 10/50 = 0.20 m/s²

Force = F = m a = 10, 000 × 0.20 = 2,000 Newtons = 2, 000 kN

Force can also be calculated as the rate of change of momentum of the bus:

= [ 10,000 × 10 - 10,000 × 0 ]/ 50  = 2000 kN