Question

A bus starts moving from rest a
and attains a velocity of 180 km/h in 1 minute 40 second
calculate acceleration of the bus in SI unit
​

Answer 1

Answer:

0.5 m/s²

Explanation:

Given:

Initial velocity = 0 m/s (u)

Final velocity = 180 km/h = $180 \times \frac{5}{18}$ = 50 m/s (v)

Time =  1 minute 40 second

1 minute = 60 seconds

1 minute 40 second = 60+40 = 100 seconds (t)

To find:

Acceleration (a)

Using the first equation of motion, which says :

v=u+at

Substituting the values, we get:

50 = 0+a×100

50 = 100a

a = $\frac{50}{100}$

a = $\frac{1}{2}$

a = $0.5 \ m/s^{2}$

The acceleration of the bus is 0.5 m/s²

Answer 2

Given :-

• Initial velocity of bus (u)=0

• Final velocity (v) =180km/h

$\dashrightarrow\sf \dfrac{5}{\cancel{18}}\times \cancel{180}= 5\times 10 =50m/s$

• v= 50m/s

• Time taken (t)= 1 min 40 sec

=> 60+40 =100seconds

To find :-

The acceleration of bus in SI unit

• SI unit of acceleration is $\sf m/s^2$

• Now by formula

$\bigstar{\boxed{\sf {Acceleration = \dfrac{final \ velocity -I nitial \ velocity}{Time \ taken}}}}$

Put the values in the formula

$\longmapsto\sf a=\dfrac{v-u}{t}\\ \\ \longmapsto\sf a=\dfrac{50-0}{100}\\ \\ \longmapsto\sf a= \cancel{\dfrac{50}{100}}\\ \\ \longmapsto\sf a= \dfrac{1}{2}m/s^2\\ \\ \longmapsto\sf a=0 .5m/s^2$

$\boxed{\sf {\dag\ \ \ Acceleration [a]=0.5m/s^2}}$