A bus starts moving in straight line with constant acceleration covers the distance AB = 180 m in 6 second. If its speed at point B is 60 m/s, then the speed of a bus at point A is
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2
Let speed at a = u m/s
Given,
S = 180m
t = 6sec
v = 60m/s
by equation of motion..
v = u + at
a = (v-u)/t
a=(60-u)/6
by equation of motion...
s= ut + 0.5at^2
180 = 6u + 0.5(60-u)/6 * 36
u= 0m/s
Given,
S = 180m
t = 6sec
v = 60m/s
by equation of motion..
v = u + at
a = (v-u)/t
a=(60-u)/6
by equation of motion...
s= ut + 0.5at^2
180 = 6u + 0.5(60-u)/6 * 36
u= 0m/s
Answered by
5
Answer is 0m/s
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