Question

A bus starts to move from rest. If it is accelerated by 0.8m/ S2 calculate the velocity and distance travelled after 8 second.​

Answer 1

Answer:

The position of bus after time t is given as x

b

=

2

1

at

2

The position of car after time t is given as x

c

=ut

Hence when the bus passes the car,

x

b

=x

c

⟹

2

1

at

2

=ut

⟹t=

a

2u

=

8m/s

2

2×16m/s

=4s

Hence the distance at the crossing=ut=16m/s×4s=64m

Answer 2

a=0.8 m/s²

t=8s

u=0

v=?

d=?

v=u+at=0+8(0.8)m/s=6.4 m/s

s=ut+1/2at²=0.8+0.8×(8)²m=64×0.8m=51.2 m