Question

A bus starts to move from rest. If it is accelerated by 4m/s2. Calculate its final velocity after 10 seconds

Answer 1

$s1=21×5t12</p><p>s2=(5t1)t2</p><p>s3=(5t1)×t3−21×5×t12=(5t1)×t1−21×5×t12</p><p>s1+s2+s3=5t1t2+5t12</p><p> \\ ⇒5t12+5t1t2=500−−−−1</p><p>2t1+t2=25−−−−2</p><p>Solving (1 ) and   (2) ⇒t1=5,t2=15sec</p><p></p><p>$

Answer 2

Answer: 40 m/s

Given:

$\sf Initial\:velocity(u)=0\:m/s (As\:the\:bus\:starts\:from\:the\:rest)$

$\sf Acceleration(a)=4m/s^2$

$\sf Time(t)=10\:s$

To find:

$\sf Final\:velocity(v).$

Formula used:

$\sf First\:Equation\:of\:Motion:\large{\boxed{\sf v=u+at}}$

Explanation:

$\sf Substituting\:the\:values\:of\:u,\:a\:and\:t\:in\:the\:formula,\:we\:get:$

$\large{\sf v=0+4\times10}$

$\large{\sf v=0+40}$

$\boxed{\large{\sf v=40\:m/s}}$

$\sf\textbf{Hence, the final velocity after 10 s is 40 m/s.}$