Question

A bus starts to move with acceleration of 1m/s2 from rest. A man who is 48m behind the bus starts to run with a constant velocity of 10m/s to catch the bus. In what time he will be catch the bus?

Answer 1

Distance travelled by bus = Distance travelled by man - 48

so 1/2 X 1 Xt2 = 10t - 48

t2 - 20t + 96 = 0

t = 8sec, 12 sec

earlier time is 8 seconds

hope it helps

Answer 2

Explanation:

time =8 sec. it is your answer